三角関数の不等式を解こう

与えられた不等式を満たすxの範囲を図示しよう。
わかりにくかったらヒントを表示してみよう。

内側，外側切り替え

ヒント表示

list1 = Sequence(((t * π / 6), 0), t, 0, 11)
sc = Random(1, 2)
A = (6.283185307179586, 0)
uchisoto = 0
UA = Point(xAxis)
UB: (x(UA), 0.25)
UD = Point(xAxis)
UC: (x(UD), 0.25)
UE = (0, 0.25)
UF = (6.28, 0.25)
C = Point(xAxis)
a = Segment(C, UE)
b = Segment(UE, UB)
c = Segment(UB, UA)
d = Segment(UB, UC)
f = If(sc ≟ 1, sin(x), cos(x))
e = Segment(UC, UD)
g = Segment(UF, A)
const = Random(-2, 2)
gl = Random(1, 2)
textgl = If(gl ≟ 1, "\geqq", "\leqq")
textsc = If(sc ≟ 1, "\sin", "\cos")
Mconst: {"+\sqrt{3}", "+1", "", "-1", "-\sqrt{3}"}
textconst = Element(Mconst, const + 3)
text1: "$2" + (LaTeX[textsc]) + " x" + (LaTeX[textconst]) + "" + (LaTeX[textgl]) + "0$"
hint = 0
h = Segment(UC, UF)
Myconst: {-0.8660254037844386, -0.5, 0, 0.5, 0.8660254037844386}
hintareaG(y) = y ≥ Element[Myconst, const + 3]
hintareaL(y) = y ≤ Element[Myconst, const + 3]
text2: "$0\leqq x < 2\pi$の範囲で，不等式" + (LaTeX[text1]) + "を満たす$x$の範囲を，
 赤い点を動かすことにより図示せよ．"